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Simplified Using Dictionary solution in Clear category for Most Wanted Letter by --Serial_Sniper--
def most_wanted(text: str) -> str:
text = text.lower()
myDict = {}
for i in text:
if i.isalpha(): myDict[i] = text.count(i)
else: continue
return [i for i in myDict if myDict[i] == max(myDict.values())]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert sorted(most_wanted("Hello World!")) == ["l"], "Hello test"
assert sorted(most_wanted("How do you do?")) == ["o"], "O is most wanted"
assert sorted(most_wanted("One")) == ["e", "n", "o"], "All letter only once."
assert sorted(most_wanted("Oops!")) == ["o"], "Don't forget about lower case."
assert sorted(most_wanted("AAaooo!!!!")) == ["a", "o"], "Only letters."
assert sorted(most_wanted("abe")) == ["a", "b", "e"], "The First."
print("Start the long test")
assert sorted(most_wanted("a" * 9000 + "b" * 1000)) == ["a"], "Long."
print("The local tests are done.")
May 21, 2020
