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First solution in Clear category for The Most Numbers by voxes96
def checkio(*args):
l = len(args)
if(l == 0):
return 0
min = args[0]
max = args[0]
for i in range(l):
if(min > args[i]):
min = args[i]
if(max < args[i]):
max = args[i]
return max-min
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Oct. 22, 2016
