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First solution in Uncategorized category for The Most Numbers by mjazy
def checkio(*args):
if len(args) < 1:
result = 0
else:
array = []
for argument in args:
array.append(argument)
print(array, 'before sort')
array.sort()
print(array)
print(array[len(array)-1]-array[0])
result = abs(array[len(array)-1]-array[0])
return result
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Jan. 22, 2018
