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First solution in Uncategorized category for The Most Numbers by marcin-krol
def maks(*args):
max = args[0]
for i in range(0, len(args)):
max = args[i] if args[i] > max else max
return max
def min(*args):
minimum = args[0]
for i in range(0, len(args)):
minimum = args[i] if args[i] < minimum else minimum
return minimum
def checkio(*args):
return 0 if len(args) == 0 else float(-min(*args) + maks(*args))
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Dec. 19, 2015
