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nice solution solution in Clear category for The Most Numbers by magda_kudrycka
def checkio(*args):
if len(args) == 0:
return 0
max = args[0]
min = args[0]
for i in range(len(args)):
if args[i] > max:
max = args[i]
if args[i] < min:
min = args[i]
return max-min
Oct. 21, 2016
