Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Uncategorized category for The Most Numbers by heigenbarth11
def checkio(*args):
amount=len(args)
if amount==0:
return 0
min=args[0]
max=args[0]
i=0
while imax):
max=args[i]
if(args[i]
Dec. 2, 2017