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First solution in Clear category for The Most Numbers by Fokzterrier
def checkio(*args):
a = list(args)
a.sort()
print(a)
c = len(a)
print(c)
if c == 0:
return 0
else:
b = a[-1] - a[0]
print(b)
return b
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
#assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
#assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
#assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(-0.07), 0, 3), "Empty"
Nov. 20, 2016
