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First solution in Clear category for The Most Numbers by Bartlomiej_Szal
def checkio(*args):
mini = 100000.0
maxi = -100000.0
if len(args) == 0:
return 0
for i in range(len(args)):
if maxi < args[i]:
maxi = args[i]
if mini > args[i]:
mini = args[i]
return maxi - mini
Oct. 9, 2016
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