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First solution in Uncategorized category for The Most Numbers by Anna_Barys
def checkio(*args):
if len(args) == 0:
d = 0
print(len(args))
else:
a = args[0]
for x in (args):
print(x)
print(a)
if x > a:
a = x
else:
a = a
print(a)
b = args[0]
for x in (args):
print(x)
print(b)
if x < b:
b = x
else:
b = b
print(b)
d = a - b
return d
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(checkio(1, 2, 3), 2, 3), "3-1=2"
assert almost_equal(checkio(5, -5), 10, 3), "5-(-5)=10"
assert almost_equal(checkio(10.2, -2.2, 0, 1.1, 0.5), 12.4, 3), "10.2-(-2.2)=12.4"
assert almost_equal(checkio(), 0, 3), "Empty"
Jan. 1, 2016
