First clear solution for Morse Encoder by Pavellver - python coding challenges

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First solution in Clear category for Morse Encoder by Pavellver

MORSE = {
    "a": ".-",
    "b": "-...",
    "c": "-.-.",
    "d": "-..",
    "e": ".",
    "f": "..-.",
    "g": "--.",
    "h": "....",
    "i": "..",
    "j": ".---",
    "k": "-.-",
    "l": ".-..",
    "m": "--",
    "n": "-.",
    "o": "---",
    "p": ".--.",
    "q": "--.-",
    "r": ".-.",
    "s": "...",
    "t": "-",
    "u": "..-",
    "v": "...-",
    "w": ".--",
    "x": "-..-",
    "y": "-.--",
    "z": "--..",
    "0": "-----",
    "1": ".----",
    "2": "..---",
    "3": "...--",
    "4": "....-",
    "5": ".....",
    "6": "-....",
    "7": "--...",
    "8": "---..",
    "9": "----.",
}


def morse_encoder(text: str) -> str:
    code = ''
    for i in text.lower():
        if i == ' ':
            code += '  '
        else:
            code += MORSE[i] + ' '
    return code.strip()
        


print("Example:")
print(morse_encoder("some text"))

assert morse_encoder("some text") == "... --- -- .   - . -..- -"
assert (
    morse_encoder("I was born in 1990")
    == "..   .-- .- ...   -... --- .-. -.   .. -.   .---- ----. ----. -----"
)

print("The mission is done! Click 'Check Solution' to earn rewards!")

March 3, 2023

Comments:

matthewwdaly on March 17, 2023, 8:10 a.m.
Well done. For a further challenge, can you figure out how to express all that logic in a single line of code? (Hint: list comprehension is a very standard and Pythonic way to combine a for loop, a conditional, and list building.)

Pavellver on March 17, 2023, 6:51 p.m.
Thank you for little challenge! I added a key {" ": " "} and easily wrote a one-line solution. def morse_encoder(text: str) -> str: return ' '.join(MORSE[i] for i in text.lower())

H0r4c3 on April 29, 2023, 11:05 a.m.
Good transformation into a one-liner!

Strings Theory

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