Gets it done (by re.findall) clear solution for Morse Decoder by martin_b - python coding challenges

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Gets it done (by re.findall) solution in Clear category for Morse Decoder by martin_b

import re

REMORSE = {'.-': 'A', '-...': 'B', '-.-.': 'C',
           '-..': 'D', '.': 'E', '..-.': 'F',
           '--.': 'G', '....': 'H', '..': 'I',
           '.---': 'J', '-.-': 'K', '.-..': 'L',
           '--': 'M', '-.': 'N', '---': 'O',
           '.--.': 'P', '--.-': 'Q', '.-.': 'R',
           '...': 'S', '-': 'T', '..-': 'U',
           '...-': 'V', '.--': 'W', '-..-': 'X',
           '-.--': 'Y', '--..': 'Z', '   ': ' ',
           '-----': '0', '.----': '1', '..---': '2',
           '...--': '3', '....-': '4', '.....': '5',
           '-....': '6', '--...': '7', '---..': '8',
           '----.': '9'
           }

def morse_decoder(c):
    return "".join(REMORSE[i] for i in re.findall("([.-]+| {3})", c)).capitalize()

April 5, 2018

Comments:

koborC on Dec. 15, 2020, 12:45 p.m.
Why did you make REMORSE uppercased ??

akomissarova on Jan. 27, 2021, 10:12 a.m.
Because it's a constant <a href="https://www.python.org/dev/peps/pep-0008/">https://www.python.org/dev/peps/pep-0008/</a>#constants

koborC on Feb. 17, 2021, 7:57 a.m.
having forgotten important community consensus. thank you!

infestum on Sept. 6, 2021, 11:57 a.m.
Nice solution, really like it. The minor thing is unnecessary grouping as spaces wouldn't clash with .- <blockquote> <pre class='brush: python'>re.findall("([.-]+| {3})", c)) </pre> </blockquote> So it could be simplified to: <blockquote> <pre class='brush: python'>re.findall("[.-]+| {3}", c)) </pre> </blockquote>

Strings Theory

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