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First solution in Clear category for Mono Captcha by yoichi
FONT = ([0, 1, 1, 0, 0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 1, 1, 0],
[0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 1, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0],
[0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0],
[0, 0, 1, 1, 0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0])
def checkio(image):
num = 0
digits = (len(image[0]) - 1) // 4
for i in range(digits):
for j in range(10):
diff = 0
for k in range(len(FONT)):
for l in range(4):
diff += FONT[k][j * 4 + l] ^ image[k][i * 4 + l]
if diff > 1:
break
else:
num = num * 10 + j
return num
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([[0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0],
[0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0],
[0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0],
[0, 1, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0]]) == 394, "394 clear"
assert checkio([[0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 0],
[0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
[0, 0, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0],
[0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0],
[0, 1, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0]]) == 394, "again 394 but with noise"
Dec. 23, 2014
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