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First solution in Uncategorized category for Monkey Typing by viktor.pecheniuk
# migrated from python 2.7
import string
def count_words(text, words):
count = 0
new_text = ''.join(x for x in text.lower() if x not in string.punctuation)
for w in words:
if w in new_text:
count+=1
return count
if __name__ == '__main__':
#These uu"1sserts" using only for self-checking and not necessary for auto-testing
assert count_words("How aresjfhdskfhskd you?", {"how", "are", "you", "hello"}) == 3, "Example"
assert count_words("Bananas, give me bananas!!!", {"banana", "bananas"}) == 2, "BANANAS!"
assert count_words("Lorem ipsum dolor sit amet, consectetuer adipiscing elit.",
{"sum", "hamlet", "infinity", "anything"}) == 1, "Weird text"
Nov. 19, 2014