First clear solution for Monkey Typing by ntcmd - python coding challenges

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First solution in Clear category for Monkey Typing by ntcmd

# migrated from python 2.7
def count_words(text, words):
    ans=0
    for i in words:
        if i in text.lower():
            ans+=1
    return ans 


if __name__ == '__main__':
    #These uu"1sserts" using only for self-checking and not necessary for auto-testing
    assert count_words("How aresjfhdskfhskd you?", {"how", "are", "you", "hello"}) == 3, "Example"
    assert count_words("Bananas, give me bananas!!!", {"banana", "bananas"}) == 2, "BANANAS!"
    assert count_words("Lorem ipsum dolor sit amet, consectetuer adipiscing elit.",
                       {"sum", "hamlet", "infinity", "anything"}) == 1, "Weird text"

Aug. 6, 2014

Comments:

rbrian on Aug. 18, 2014, 11:26 p.m.
I like how you added text.lower() after the if. I had a separate line before the for loop with text= text.lower()

dan.garthwaite on Aug. 29, 2014, 2:24 p.m.
I would prefer to remove it outside the loop - so that it isn't being executed over and over.

rbrian on Aug. 29, 2014, 2:27 p.m.
Hmm... I see your point. I had not thought of that.

AraytShah on Oct. 23, 2014, 1:44 p.m.
Using <a href="https://docs.python.org/3/tutorial/datastructures.html#list-comprehensions">list comprehension</a>, can you figure out how count the words without a counter?

mlb00 on March 17, 2015, 7:47 p.m.
This is a good idea, thanks!

dimitrioschr on Jan. 26, 2015, 2:02 p.m.
try to come up with a solution more natural to python, e.g. a set comprehension...

Lucy2015 on May 25, 2015, 2:37 a.m.
The same as you.^_^ The first solution in this list is too difficult to understand for me at present.

jakow on Sept. 13, 2015, 4:06 p.m.
wow, the same as my solution

DeCooper on Sept. 11, 2017, 7:37 p.m.
Have to give this solution two thumbs up, as it's the same as mine. ;-)

belary on July 23, 2018, 2:13 a.m.
<pre class='brush: python'>word = 'Bananas, give me bananas!!!'; print 'bananas' in word.lower() </pre> I didn't know why this return "TRUE", but your solution return "FALSE"

ljwoodward on Oct. 26, 2018, 1:23 p.m.
Probably less cumbersome to do this without a counter

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