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First solution in Clear category for Min and Max by yama_k_1101
def compare(args, kwargs, operation):
key = kwargs.get("key", lambda v: v)
if len(args) == 1:
# get target iterable object.
args = args[0]
result = None
for v in args:
compared_value = key(v)
if result is None or operation(compared_value, result[0]):
result = (compared_value, v)
return result[1]
def min(*args, **kwargs):
less_than = lambda a,b: a < b
return compare(args, kwargs, less_than)
def max(*args, **kwargs):
greater_than = lambda a,b: a > b
return compare(args, kwargs, greater_than)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Jan. 4, 2015
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