Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
min max solution in Clear category for Min and Max by wojtekpaciej
def minSimple(arg1, arg2, key):
if key!=None and key(arg1)key(arg1) or key==None and arg2>arg1: return arg2
return arg1
def max(*args, **kwargs):
key=kwargs.get("key", None)
if len(args)==1: args=list(args[0])
result=args[0]
for x in range(1,len(args)):
result=maxSimple(result,args[x],key)
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Dec. 12, 2016
