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First solution in Clear category for Min and Max by plutasnyy
def min(*args, **kwargs):
funkcja = kwargs.get("key", lambda x: x)
if len(args) == 1:
lista = args[0]
else:
lista = args[:]
pom=None
for i in lista:
if pom == None:
pom = i
if funkcja(i) < funkcja(pom):
pom = i
return pom
def max(*args, **kwargs):
funkcja = kwargs.get("key", lambda x: x)
if len(args) == 1:
lista = args[0]
else:
lista=args[:]
pom=None
for i in lista:
if pom == None:
pom = i
if funkcja(i) > funkcja(pom):
pom = i
return pom
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert min(3, 2) == 2, "Simple case min"
# assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
#assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Oct. 29, 2016
