Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Min and Max by nakanolab
def min(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
v = None
if len(args) == 1: args = args[0]
for i, arg in enumerate(args):
if i == 0:
v = arg
elif key(arg) < key(v):
v = arg
return v
def max(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
v = None
if len(args) == 1: args = args[0]
for i, arg in enumerate(args):
if i == 0:
v = arg
elif key(arg) > key(v):
v = arg
return v
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
May 8, 2015
