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First solution in Clear category for Min and Max by mgugala
def extreme(comparator, *args, **kwargs):
key = kwargs.get('key', lambda x: x)
if len(args) == 1:
args = next(iter(args))
iterator = iter(args)
result = next(iterator)
for arg in iterator:
if comparator(key(arg), key(result)):
result = arg
return result
def min(*args, **kwargs):
return extreme(lambda x, y: x < y, *args, **kwargs)
def max(*args, **kwargs):
return extreme(lambda x, y: x > y, *args, **kwargs)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Jan. 12, 2018
