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Clear solution in Clear category for Min and Max by martin_b
import operator
def min_max(c, *args, **kwargs):
key = kwargs.get("key", lambda x: x)
i = iter(args if len(args) > 1 else args[0])
m = next(i)
for e in i:
if c(key(e), key(m)):
m = e
return m
def min(*args, **kwargs):
return min_max(operator.lt, *args, **kwargs)
def max(*args, **kwargs):
return min_max(operator.gt, *args, **kwargs)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Dec. 22, 2015
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