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First solution in Clear category for Min and Max by lukas.linhart
def minmax(comparator, *args, **kwargs):
key = kwargs.get("key", None)
items = list(*args) if len(args) == 1 else list(args)
res = items[0]
for item in items[1:]:
if comparator(key(item) if key else item, key(res) if key else res):
res = item
return res
min = lambda *args, **kwargs: minmax(lambda a, b: a < b, *args, **kwargs)
max = lambda *args, **kwargs: minmax(lambda a, b: a > b, *args, **kwargs)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
March 1, 2015
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