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First solution in Clear category for Min and Max by dominieq
def sorting (list, newkey, condition):
if len(list) == 1:
list = list[0]
first_result = sorted(list, key=newkey, reverse=condition)
return first_result[0]
def min(*args, **kwargs):
mkey = kwargs.get("key", None)
final_result = sorting(args, mkey, False)
return final_result
def max(*args, **kwargs):
mkey = kwargs.get("key", None)
final_result = sorting(args, mkey, True)
return final_result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Oct. 26, 2016
