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lambda lambda reduce lambda solution in Creative category for Min and Max by StefanPochmann
import operator, functools
min, max = map(lambda lt: lambda *args, key=lambda x:x:
functools.reduce(lambda a,b: b if lt(key(b), key(a)) else a,
args[0] if len(args) < 2 else args),
(operator.lt, operator.gt))
April 17, 2015