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sorted solution in Uncategorized category for Min and Max by Sim0000
def min(*args, key=lambda x:x):
return sorted(args[0] if len(args) == 1 else args, key=key)[0]
def max(*args, key=lambda x: x):
return sorted(args[0] if len(args) == 1 else args, key=key, reverse = True)[0]
May 8, 2014
