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First solution in Clear category for Min and Max by Plaix
def min(*args, **kwargs):
key = kwargs.get("key", None)
argv = args if len(args) > 1 else args[0]
if not isinstance(argv, list):
argv = list(argv)
small = argv[0]
if key:
for val in argv:
if key(val) < key(small):
small = val
else:
for val in argv:
if val < small:
small = val
return small
def max(*args, **kwargs):
key = kwargs.get("key", None)
argv = args if len(args) > 1 else args[0]
if not isinstance(argv, list):
argv = list(argv)
big = argv[0]
if key:
for val in argv:
if key(val) > key(big):
big = val
else:
for val in argv:
if val > big:
big = val
return big
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
June 25, 2015
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