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ONE LINE solution in Clear category for Min and Max by Noboru__Tanase
def min(*args, **kwargs):return sorted(args if len(args) > 1 else args[0],key=kwargs.get("key", None))[0]
def max(*args, **kwargs):return sorted(args if len(args) > 1 else args[0],key=kwargs.get("key", None),reverse=True)[0]
July 23, 2017
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