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First solution in Clear category for Min and Max by MarcAureleCoste
def get_iterable(elements):
if len(elements) == 1:
return elements[0]
return elements
def get_comp_value(v1, v2, key):
if v1 is not None and key:
v1 = key(v1)
v2 = key(v2)
return v1, v2
def min(*args, **kwargs):
key = kwargs.get("key", None)
res = None
for e in get_iterable(args):
v1, v2 = get_comp_value(res, e, key)
res = e if res is None else e if v1 > v2 else res
return res
def max(*args, **kwargs):
key = kwargs.get("key", None)
res = None
for e in get_iterable(args):
v1, v2 = get_comp_value(res, e, key)
res = e if res is None else e if v1 < v2 else res
return res
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Aug. 22, 2018
