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First solution in Clear category for Min and Max by LMAO
def min(*args, **kwargs):
key = kwargs.get("key")
if len(args) == 1:
args = args[0]
return sorted(args, key=key)[0]
def max(*args, **kwargs):
key = kwargs.get("key")
if len(args) == 1:
args = args[0]
return sorted(args, key=key, reverse=True)[0]
Feb. 22, 2015
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