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First solution in Uncategorized category for Min and Max by Degusto
def min(*args, **kwargs):
key = kwargs.get("key", None)
min = args[0]
if len(args) == 1:
args = list(args[0])
min = args[0]
for arg in args:
if key is not None:
if key(min) > key(arg):
min = arg
elif min > arg:
min = arg
return min
def max(*args, **kwargs):
key = kwargs.get("key", None)
max = args[0]
if len(args) == 1:
args = list(args[0])
max = args[0]
for arg in args:
if key is not None:
if key(max) < key(arg):
max = arg
elif max < arg:
max = arg
return max
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max([1, 2, 0, 3, 4]) == 4, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
Nov. 17, 2015
