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MM solution in Clear category for Min and Max by Anaaa
def min(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
cmp_args = args if len(args) > 1 else args[0]
min_arg = None
for arg in cmp_args:
if min_arg is None or key(arg) < key(min_arg):
min_arg = arg
return min_arg
def max(*args, **kwargs):
key = kwargs.get("key", lambda x: x)
cmp_args = args if len(args) > 1 else args[0]
max_arg = None
for arg in cmp_args:
if max_arg is None or key(arg) > key(max_arg):
max_arg = arg
return max_arg
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert max(3, 2) == 3, "Simple case max"
assert min(3, 2) == 2, "Simple case min"
assert max([1, 2, 0, 3, 4]) == 4, "From a list"
assert min("hello") == "e", "From string"
assert max(2.2, 5.6, 5.9, key=int) == 5.6, "Two maximal items"
assert min([[1, 2], [3, 4], [9, 0]], key=lambda x: x[1]) == [9, 0], "lambda key"
July 21, 2015
