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a long and a short solution solution in Clear category for Median by lucas.stonedrake
import statistics as st
#1st solution using statistics module
def checkio(data) -> [int, float]:
return st.median(data)
#2nd solution, long method
def checkio(data) -> [int, float]:
#return the entry at the middle index if the length of data is even
if len(data) % 2 != 0: return sorted(data)[len(data) // 2]
# return the mean of the entries at the two middle indices if the length of data is odd
else: return (sorted(data)[(len(data) // 2)] + sorted(data)[(len(data) // 2) - 1]) / 2
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print("Example:")
print(checkio([1, 2, 3, 4, 5]))
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("Coding complete? Click 'Check' to earn cool rewards!")
Oct. 22, 2020
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