First clear solution for Median by Ziemowit_Soko_owski - python coding challenges

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First solution in Clear category for Median by Ziemowit_Soko_owski

def checkio(data):

   sor = sorted(data)
   
   if len(sor) % 2 == 1:
       return sor[len(sor) // 2]
   elif len(sor) % 2 == 0:
       return ((sor[len(sor) // 2] + sor[len(sor) // 2 -1])/2)

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
    assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
    assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
    assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
    print("Start the long test")
    assert checkio(list(range(1000000))) == 499999.5, "Long."
    print("The local tests are done.")

Oct. 22, 2016

Comments:

DerryK on Dec. 15, 2016, 12:39 a.m.
<p>Simple and straightforward. Except you could replace the "elif len(sor) %2 == 0" with a simple "else"; there are no other choices but 1 and 0.</p>

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