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Clean and Simple solution in Clear category for Median by Pemdas
def checkio(data):
#Creates a sorted list of data
LSort = sorted(data)
#Finds the Lenth of data and then divides by 2 to find middle
Mid = int((len(LSort)/2))
#If length of data divided by 2 ==0
if len(LSort) % 2 == 0:
#Average middle two numbers
Median = (int(LSort[Mid])+int(LSort[Mid-1]))/2
else :
#Return middle Number from LSort
Median = LSort[Mid]
return Median
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("The local tests are done.")
May 8, 2015
