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Using .sort() solution in Clear category for Median by Hawful
def checkio(data):
data.sort()
mid = len(data)//2
if len(data) % 2:#A remainder makes this true, meaning it is odd.
return data[mid]
else:
result = (data[mid]+data[mid-1])/2
return result
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("The local tests are done.")
Jan. 4, 2016