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First solution in Speedy category for Median by Arandomusername
def checkio(data):
len_ = len(data)
data.sort()
return data[len_//2] if len_ & 1 else (data[len_//2] + data[(len_//2) - 1]) / 2
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio([1, 2, 3, 4, 5]) == 3, "Sorted list"
assert checkio([3, 1, 2, 5, 3]) == 3, "Not sorted list"
assert checkio([1, 300, 2, 200, 1]) == 2, "It's not an average"
assert checkio([3, 6, 20, 99, 10, 15]) == 12.5, "Even length"
print("Start the long test")
assert checkio(list(range(1000000))) == 499999.5, "Long."
print("The local tests are done.")
Feb. 26, 2015
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