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First solution in Clear category for Median of Three by wo.tomasz
from typing import Iterable
def median_three(els: Iterable[int]) -> Iterable[int]:
ne = []
for i in range(len(els)):
if i < 2:
ne.append(els[i])
else:
ne.append(sorted([els[i-2],els[i-1],els[i]])[1])
return ne
if __name__ == '__main__':
print("Example:")
print(list(median_three([1, 2, 3, 4, 5, 6, 7])))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(median_three([1, 2, 3, 4, 5, 6, 7])) == [1, 2, 2, 3, 4, 5, 6]
assert list(median_three([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 28, 2020
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