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without busting solution in Clear category for Long Repeat by oldjaponec
import re
a=re.compile(r'(?=(.)\1{1,})(\1+)')
def long_repeat(l):
if len(l)>0:
if a.search(l): m=len(max(a.findall(l)[-1]))
else: m=1
else: m=0
return m
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
Sept. 2, 2019
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