Second creative solution for Long Repeat by juestr - python coding challenges

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Second solution in Creative category for Long Repeat by juestr

def long_repeat(line):
    prev, count, m = None, 0, 0
    for x in line:
        count = x != prev or count + 1
        prev, m = x, max(m, count)
    return m

June 12, 2019

Comments:

FirstShanti on Sept. 9, 2019, 11:43 p.m.
Look like easy)

burlakov16 on Nov. 5, 2019, 4:01 p.m.
Very good!

jiizzyy on Feb. 5, 2020, 1:45 a.m.
Cleanly build!

t.prozorov on March 29, 2020, 6:31 a.m.
Hello, i have tried with your solution and found one issue: when we have line = 'a' or another singal item we get a wrong result (m = True). I recommend fix the code: <pre class='brush: python'>def long_repeat(line): prev, count, m = None, 0, 0 for x in line: count = int(x != prev) or count + 1 # form "int(x != prev)" transform "True" to 1 and give as the first count of string prev, m = x, max(m, count) return m </pre> But i can't understand the line "prev, m = x, max(m, count)". What we exactly do in this part of code? It will be appreciated to see your comment.

juestr on March 29, 2020, 12:41 p.m.
Please note that `True == 1` is true, as is `issubclass(bool, int)` or `isinstance(True, int)`, so `True` really is-an `int` of value `1` and there's no need to convert it. It's also the main reason this solution is filed under creative. As for the parallel assignment, let's break it down: <pre class='brush: python'>prev = x # memorize the current x for the next loop iteration m = max(m, count) # m is global maximum repeat ever seen </pre>

Strings Theory

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