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Regex solution in Clear category for Long Repeat by igor.v.dudenko
import re
def long_repeat(line):
"""
length the longest substring that consists of the same char
"""
if not line:
return 0
pattern = r'([a-z])\1{1,}'
matches = [x.group() for x in re.finditer(pattern, line)]
if matches:
return len(max(matches, key=len))
else:
return 1
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
Feb. 13, 2019
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