Long Repeat - Speedy speedy solution for Long Repeat by Ledorub - python coding challenges

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Long Repeat - Speedy solution in Speedy category for Long Repeat by Ledorub

long_repeat = lambda line: len(max(__import__("re").findall(r"{}+".format("+|".join(list(set(line)))), line), key=len)) if line else 0

Aug. 13, 2017

Comments:

Ledorub on Sept. 1, 2017, 3:40 p.m.
UPD: You can delete list func inside join method, it's unnecessary.

andna on Aug. 12, 2019, 1:18 a.m.
try also <pre class='brush: python'>re.findall(r'((.)\2+)', line) </pre> or <pre class='brush: python'>re.findall(r'((\w)\2+)', line) </pre> ...but yours would be faster, nevermind

Strings Theory

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