3th speedy solution for Long Repeat by Crachton - python coding challenges

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3th solution in Speedy category for Long Repeat by Crachton

from itertools import groupby

def long_repeat(string):
    if not string: return 0
    return max(len(list(g)) for _,g in groupby(string))

Oct. 18, 2017

Comments:

IvanowDenis on Dec. 16, 2017, 10:27 p.m.
Nice. Now I know about groupby from itertools.

dunaldo on July 15, 2018, 11:43 a.m.
Awesome! Itertools will save the world!

Kairat on Nov. 9, 2020, 3:41 p.m.
itertools.groupby exactly fits to the task. And that's the rare case where pre-sorting not needed.

lxf42 on May 25, 2022, 8:27 a.m.
very nice idea to use groupby, this challenge is the perfect use for it and makes the code so readable

Wartem on Dec. 14, 2022, 1:36 p.m.
Simple, easy to understand and short. But compound statements (multiple statements on the same line) are generally discouraged.

Pactp on June 16, 2023, 8:01 a.m.
Simple, nice and short. It's easy to convert it to oneliner: <pre class='brush: python'>long_repeat = lambda s: max(len(list(g)) for _,g in groupby(s))if s else 0 </pre>

pavel.fasther on Aug. 3, 2023, 5:25 p.m.
I would recommend putting that "return" on another line - it is possible to do it like this, but hurts readability.

Strings Theory

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