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First - Re.findall solution in Clear category for Long Repeat by Chnelik_Sebastian
def long_repeat(line) -> int:
#We check for no empty input and no matches. Then, extract all sequences, sort, and len the longest.
import re
if len(line)==0:
return 0
match=re.findall("(([a-z])\\2{1,})", line)
if len(match)==0:
return 1
seql=list(x for (x,y) in match)
seqmax=sorted(seql, key=len, reverse=True)[0]
return len(seqmax)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert long_repeat('sdsffffse') == 4, "First"
assert long_repeat('ddvvrwwwrggg') == 3, "Second"
assert long_repeat('abababaab') == 2, "Third"
assert long_repeat('') == 0, "Empty"
print('"Run" is good. How is "Check"?')
Sept. 11, 2019
