Third clear solution for Letter Queue by khanukov - python coding challenges

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Third solution in Clear category for Letter Queue by khanukov

def letter_queue(commands):
    ans=""
    for c in commands:
        if (c[:4]=="PUSH"): ans=ans+c[5:]  
        else: ans=ans[1:]  
    return ans

April 17, 2015

Comments:

Kverde on Aug. 13, 2022, 9:28 a.m.
<p>I think it could be little more readable if you change lines 4 and 5</p> <pre class='brush: python'> if (c == "POP"): ans = ans[1:] else: ans = ans + c[-1] </pre>

Strings Theory

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