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First solution in Clear category for Largest Rectangle in a Histogram by Bartlomiej_Szal
def rectangleSize(bars):
return min(bars)*len(bars)
def largest_histogram(histogram):
tempBarList = []
tempBarList.append(histogram[0])
maxRectangleSize = rectangleSize(tempBarList)
for x in range(len(histogram)):
tempBarList = []
tempBarList.append(histogram[x])
if rectangleSize(tempBarList) > maxRectangleSize:
maxRectangleSize = rectangleSize(tempBarList)
for y in range(x + 1,len(histogram)):
tempBarList.append(histogram[y])
if rectangleSize(tempBarList) > maxRectangleSize:
maxRectangleSize = rectangleSize(tempBarList)
return maxRectangleSize
if __name__ == "__main__":
#These "asserts" using only for self-checking and not necessary for auto-testing
assert largest_histogram([5]) == 5, "one is always the biggest"
assert largest_histogram([5, 3]) == 6, "two are smallest X 2"
assert largest_histogram([1, 1, 4, 1]) == 4, "vertical"
assert largest_histogram([1, 1, 3, 1]) == 4, "horizontal"
assert largest_histogram([2, 1, 4, 5, 1, 3, 3]) == 8, "complex"
print("Done! Go check it!")
Nov. 4, 2016
