First clear solution for Just Fizz! by juestr - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

First solution in Clear category for Just Fizz! by juestr

def checkio(num: int) -> str:
    return str(num) if num % 3 else 'Fizz'

Nov. 28, 2022

Comments:

Mishytca on July 2, 2023, 12:24 p.m.
<p>If the input number num is divisible by 3 (i.e., num % 3 evaluates to 0), the function returns the string 'Fizz'. If the input number num is not divisible by 3, the function returns the string representation of num. In other words, if the input number is divisible by 3, it returns 'Fizz'; otherwise, it returns the string representation of the number.</p>

Strings and Integers

0 %

PyCharm The Python IDE for Professional Developers. Enjoy productive Python, web and scientific development with PyCharm. Download it now!