First clear solution for Surjection Strings by dx2-66 - python coding challenges

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First solution in Clear category for Surjection Strings by dx2-66

def isometric_strings(a, b):
    d = {}
    for c1, c2 in zip(a,b):
        if c1 not in d:
            d[c1] = c2
        elif d[c1] != c2:
            return False
    return True

April 21, 2022

Comments:

jakubbortlik on Dec. 5, 2022, 9:19 a.m.
<p>Nice clear solution.</p> <p>Note that `if c1 not in d: d[c1] = c2` is implemented as `dict.setdefault(c1, c2)`. The benefit of this approach is that `dict.setdefault()` returns the value if the key already is in the dictionary, so you can simplify lines 4-7 to: ``` if c2 != d.setdefault(c1, c2): return False ```</p>

Strings Theory

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