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Miu solution in Clear category for Index Power by caitlan
def index_power(array: list, n: int) -> int:
"""
Find Nth power of the element with index N.
"""
if n>(len(array)-1):
return -1
else:
return pow(array[n],n)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert index_power([1, 2, 3, 4], 2) == 9, "Square"
assert index_power([1, 3, 10, 100], 3) == 1000000, "Cube"
assert index_power([0, 1], 0) == 1, "Zero power"
assert index_power([1, 2], 3) == -1, "IndexError"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
April 17, 2019
