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Math power solution in Clear category for Index Power by Striga
def index_power(array: list, n: int) -> int:
return array[n]**n if len(array) > n else -1
if __name__ == '__main__':
assert index_power([1, 2, 3, 4], 2) == 9, "Square"
assert index_power([1, 3, 10, 100], 3) == 1000000, "Cube"
assert index_power([0, 1], 0) == 1, "Zero power"
assert index_power([1, 2], 3) == -1, "IndexError"
Oct. 7, 2020
