1-liner speedy solution for Index Power by Stensen - python coding challenges - Py.CheckiO

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1-liner solution in Speedy category for Index Power by Stensen

index_power = lambda i, j: i[j]**j if len(i)>j else -1

Sept. 21, 2020

Comments:

Vykers on Nov. 10, 2021, 5:03 p.m.
<p>probably the shortest one I've seen, nice use of ternary operator)</p>

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