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Formula solution in Clear category for Humpty Dumpty Form by bryukh
# Using formulas from http://en.wikipedia.org/wiki/Spheroid
from math import pi, asin, atanh
def checkio(height, width):
"""
Calculate the volume and the surface area for the spheroid.
Args:
height: spheroid's height.
width: spheroid's width.
Returns:
the list with the volume and the surface area. Rounded at two digits.
"""
a, c = width / 2, height / 2
volume = (4 / 3) * pi * c * (a ** 2)
#prolate
if a < c:
e = (1 - a ** 2 / c ** 2) ** 0.5
area = 2 * pi * a ** 2 * (1 + asin(e) * c / (a * e))
#oblate
elif a > c:
e = (1 - c ** 2 / a ** 2) ** 0.5
area = 2 * pi * a ** 2 * (1 + atanh(e) * (1 - e ** 2) / e)
# sphere
else:
area = 4 * pi * a ** 2
return [round(volume, 2), round(area, 2)]
Feb. 6, 2014
